The reaction of propene with HBr in peroxide proceeds through the intermediate

Question

The reaction of propene with HBr in peroxide proceeds through the intermediate (A) H3C - underset bullet C - CH3  (B) H3C - underset bulletC - CH2 Br  (C) H3C - overset underset|BrCH - overset bulletCH2 (D)  H3C - CH2 - overset bullet C H2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/7097c29782b79d61507bd353704d723d-.png" /> The intermediate produce in case of addition of HBr occurs according to antimarkonicov's rule. Thus we get CH 3- overset bulletCH - CH 2 Br as intermidiate.

Q. The reaction of propene with $H B r$ in peroxide proceeds through the intermediate

$H_{3} C - ∙ C - C H_{3}$

$H_{3} C - ∙ C - C H_{2} B r$

$H_{3} C - C H ∣ B r - C ∙ H_{2}$

$H_{3} C - C H_{2} - C ∙ H_{2}$

None of the above

The intermediate produce in case of addition of $H B r$ occurs according to antimarkonicov's rule. Thus we get

$C H_{3} - C ∙ H - C H_{2} B r$ as intermidiate.

Q. The reaction of propene with HBr in peroxide proceeds through the intermediate

H3​C−∙C​−CH3​

H3​C−∙C​−CH2​Br

H3​C−CH∣Br​−C∙H2​

H3​C−CH2​−C∙H2​