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Chemistry
The reaction of propene with HBr in peroxide proceeds through the intermediate
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Q. The reaction of propene with $HBr$ in peroxide proceeds through the intermediate
KEAM
KEAM 2017
Hydrocarbons
A
$H_3C - \underset{ \bullet} {C} - CH_3 $
9%
B
$H_3C - \underset{\bullet}{C} - CH_2 Br $
45%
C
$H_3C - \overset{\underset{|}{Br}}{CH} - \overset{\bullet}{C}H_2$
27%
D
$ H_3C - CH_2 - \overset{ \bullet}{ C} H_2$
9%
E
None of the above
9%
Solution:
The intermediate produce in case of addition of $HBr$ occurs according to antimarkonicov's rule. Thus we get
$CH _{3}- \overset{\bullet}{C}H - CH _{2} Br$ as intermidiate.