The reaction of ethyl methyl ketone with Cl2/excess OH- gives the following major product

Question

The reaction of ethyl methyl ketone with Cl2/excess OH- gives the following major product (A) ClCH2CH2COCH3 (B) CH3CH2COCCl3 (C) ClCH2CH2COCH2Cl (D) CH3CCl2COCH2Cl

Tardigrade Admin · Accepted Answer

As α-hydrogen to carbonyl group is more acidic gets attacked by strong OH- base to form enol which then attack by Cl2 molecule to give chlorinated product.

Q. The reaction of ethyl methyl ketone with $C l_{2}$ /excess $O H^{-}$ gives the following major product

$ClC H_{2} C H_{2} COC H_{3}$

$C H_{3} C H_{2} COCC l_{3}$

$ClC H_{2} C H_{2} COC H_{2} Cl$

$C H_{3} CC l_{2} COC H_{2} Cl$

As $α$ -hydrogen to carbonyl group is more acidic gets attacked by strong $O H^{-}$ base to form enol which then attack by $C l_{2}$ molecule to give chlorinated product.

Q. The reaction of ethyl methyl ketone with Cl2​/excess OH− gives the following major product

ClCH2​CH2​COCH3​

CH3​CH2​COCCl3​

ClCH2​CH2​COCH2​Cl

CH3​CCl2​COCH2​Cl