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Q. The reaction of ethyl methyl ketone with $Cl_2$/excess $OH^{-}$ gives the following major product

KVPYKVPY 2013Aldehydes Ketones and Carboxylic Acids

Solution:

As $\alpha$-hydrogen to carbonyl group is more acidic gets attacked by strong $OH^{-}$ base to form enol which then attack by $Cl_2$ molecule to give chlorinated product.
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