The reaction of chlorine-water with propene gives

Question

The reaction of chlorine-water with propene gives (A) ClCH2-CH(.OH.)CH3 (B) CH2(.OH.)CH(.Cl.)CH3 (C) ClCH2CH2CH2OH (D) ClCH(.OH.)CH2CH3

Tardigrade Admin · Accepted Answer

Addition of Cl2 (aq) (or HO-Cl) occurs according to Markownikov's rule as follows: <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-cxsbrit0brk3.png" /> Here +ve part of addendum goes to the carbon atom of double bond that has more hydrogens and the negative part and the negative part is added to the unsaturated carbon with less hydrogen.

Q. The reaction of chlorine-water with propene gives

$ClC H_{2} - C H (O H) C H_{3}$

$C H_{2} (O H) C H (Cl) C H_{3}$

$ClC H_{2} C H_{2} C H_{2} O H$

$ClC H (O H) C H_{2} C H_{3}$

Addition of $C l_{2} (a q)$ (or $H O - Cl)$ occurs according to Markownikov's rule as follows:

Here +ve part of addendum goes to the carbon atom of double bond that has more hydrogens and the negative part and the negative part is added to the unsaturated carbon with less hydrogen.

Q. The reaction of chlorine-water with propene gives

ClCH2​−CH(OH)CH3​

CH2​(OH)CH(Cl)CH3​

ClCH2​CH2​CH2​OH

ClCH(OH)CH2​CH3​

Addition of Cl2​(aq) (or HO−Cl) occurs according to Markownikov's rule as follows: Here +ve part of addendum goes to the carbon atom of double bond that has more hydrogens and the negative part and the negative part is added to the unsaturated carbon with less hydrogen.

$ClC H_{2} - C H (O H) C H_{3}$

$C H_{2} (O H) C H (Cl) C H_{3}$

$ClC H_{2} C H_{2} C H_{2} O H$

$ClC H (O H) C H_{2} C H_{3}$

Addition of $C l_{2} (a q)$ (or $H O - Cl)$ occurs according to Markownikov's rule as follows:

Here +ve part of addendum goes to the carbon atom of double bond that has more hydrogens and the negative part and the negative part is added to the unsaturated carbon with less hydrogen.