Question

The reaction of chlorine-water with propene gives

• A. $ClCH_{2}-CH\left(\right.OH\left.\right)CH_{3}$
• B. $CH_{2}\left(\right.OH\left.\right)CH\left(\right.Cl\left.\right)CH_{3}$
• C. $ClCH_{2}CH_{2}CH_{2}OH$
• D. $ClCH\left(\right.OH\left.\right)CH_{2}CH_{3}$

Answer 1

Answer: (A)

Addition of $Cl_{2} (aq)$ (or $HO-Cl)$ occurs according to Markownikov's rule as follows:



Here +ve part of addendum goes to the carbon atom of double bond that has more hydrogens and the negative part and the negative part is added to the unsaturated carbon with less hydrogen.