The reaction A longrightarrow C proceeds through two paths I and II as shown below: The correct relationship between Δ H, Δ H1 and Δ H2 will be

Question

The reaction A longrightarrow C proceeds through two paths I and II as shown below: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/2039ef471ecf93554adbccd15ebf86c8-.png" /> The correct relationship between Δ H, Δ H1 and Δ H2 will be (A) Δ H=Δ H2-Δ H1 (B) Δ H=Δ H1 / Δ H2 (C) Δ H=Δ H1+Δ H2 (D) Δ H=Δ H1 × Δ H2

Tardigrade Admin · Accepted Answer

According to Hess's law; the total heat change

(Δ H)

accompanying a chemical reaction is the same, whether the reaction takes place in one or more steps or follows one or more paths.
Therefore, the correct relation between

Δ H

and

Δ H_{1}, Δ H_{2}

will be

Δ H = Δ H_{1} + Δ H_{2}

Q. The reaction $A ⟶ C$ proceeds through two paths I and II as shown below :

The correct relationship between $Δ H, Δ H_{1}$ and $Δ H_{2}$ will be

$Δ H = Δ H_{2} - Δ H_{1}$

$Δ H = Δ H_{1} /Δ H_{2}$

$Δ H = Δ H_{1} + Δ H_{2}$

$Δ H = Δ H_{1} \times Δ H_{2}$

According to Hess's law; the total heat change $(Δ H)$ accompanying a chemical reaction is the same, whether the reaction takes place in one or more steps or follows one or more paths.
Therefore, the correct relation between $Δ H$ and $Δ H_{1}, Δ H_{2}$ will be
$Δ H = Δ H_{1} + Δ H_{2}$

Q. The reaction A⟶C proceeds through two paths I and II as shown below : The correct relationship between ΔH,ΔH1​ and ΔH2​ will be

ΔH=ΔH2​−ΔH1​

ΔH=ΔH1​/ΔH2​

ΔH=ΔH1​+ΔH2​

ΔH=ΔH1​×ΔH2​