Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The reaction A+B→ C+D+40 kJ has an activation energy of 18 kJ. Then the activation energy for the reaction C+D→ A+B is
Q. The reaction
A
+
B
→
C
+
D
+
40
k
J
has an activation energy of
18
k
J
. Then the activation energy for the reaction
C
+
D
→
A
+
B
is
3318
217
J & K CET
J & K CET 2011
Chemical Kinetics
Report Error
A
58
k
J
34%
B
−
40
k
J
17%
C
−
18
k
J
23%
D
22
k
J
25%
Solution:
A
+
B
→
C
+
D
+
40
k
J
∵
Activation energy for the forward reaction,
A
+
B
→
C
+
D
=
18
k
J
∴
Activation energy for the reverse reaction,
C
+
D
→
A
+
B
=
40
+
18
=
58
k
J