1. Tardigrade
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  3. Chemistry
  4. The reaction A+B→ C+D+40 kJ has an activation energy of 18 kJ. Then the activation energy for the reaction C+D→ A+B is

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Q. The reaction $ A+B\to C+D+40\,kJ $ has an activation energy of $18\, kJ$. Then the activation energy for the reaction $ C+D\to A+B $ is

J & K CETJ & K CET 2011Chemical Kinetics

Solution:

$ A+B \rightarrow C+D+40\,kJ $
$ \because $ Activation energy for the forward reaction,
$ A+B\rightarrow C+D=18\,kJ $
$ \therefore $ Activation energy for the reverse reaction,
$ C+D\rightarrow A+B=40+18=58\,kJ $