Question

The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction $2A+4B\to 3C+4D$, when $5$ moles of $A$ react with $6$ moles of $B$, then which is the limiting reagent and what would be the amount of $C$ formed respectively?

• A. $C,4.5$ mol
• B. $B,4.5$ mol
• C. $B,3.5$ mol
• D. $C,4.0$ mol

Answer 1

Answer: (B)

In the reaction, $2A+4B\to 3C+4D$
$2$ moles of $A$ react with $4$ moles of $B$
$5$ moles of $A$ will react with $\frac{4}{2}\times 10$ moles of $B$
Since in the reaction only $6$ moles of $B$ are there, hence $B$ is the limiting reagent.
Now, $4$ moles of $B$ give $3$ moles of $C$
$6$ moles of $B$ will give $\frac{3}{4}\times 6=4.5$ mol of $C$