Question

The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction $2A + 4B \to 3C + 4D$, when $5$ moles of $A$ react with $6$ moles of $B$, then which is the limiting reagent and what would be the amount of $C$ formed respectively?

• A. $C, 4.5$ mol
• B. $B, 4.5$ mol
• C. $B, 3.5$ mol
• D. $C, 4.0$ mol

Answer 1

Answer: (B)

In the reaction, $2A + 4B \to 3C + 4D$
$2$ moles of $A$ react with $4$ moles of $B$
$5$ moles of $A$ will react with $\frac{4}{2}\times10$ moles of $B$
Since in the reaction only $6$ moles of $B$ are there, hence $B$ is the limiting reagent.
Now, $4$ moles of $B$ give $3$ moles of $C$
$6$ moles of $B$ will give $\frac {3}{4}\times6 = 4.5 $ mol of $C$