Question

The ratio of time constant in charging and discharging in the circuit shown in the figure is $\frac{x}{y}$. Find $(x+y)$

Answer 1

Answer: 5

Parallel combination of resistor and battery will give only battery.
So, charging time constant, ${\tau }_c=\frac{L}{2R}$

Now $R$ and $2R$ are in series.
So, discharging time constant, ${\tau }_D=\frac{L}{3R}$
${\tau }_C:{\tau }_D=\frac{L}{2R}:\frac{L}{3R}=3:2$