Question

The ratio of the radii of the nuclei ${}_{13}A{I}^{27}$ and ${}_{52}T{e}^{125}$ approximately

• A. 6:10
• B. 13:52
• C. 40:177
• D. 14:73

Answer 1

Answer: (A)

$R=(A{)}^{1/3}$ from $R=R_0{A}^{1/3}$
$\therefore R_{AI}=(27{)}^{1/3}$ and $R_{Te}=(125{)}^{1/5}$
$\therefore \frac{R_{AI}}{R_{Te}}=\frac{3}{5}=\frac{6}{10}$