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  4. The ratio of the radii of the nuclei 13 AI 27 and 52 Te 125 approximately

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Q. The ratio of the radii of the nuclei ${ }_{13} AI ^{27}$ and ${ }_{52} Te ^{125}$ approximately

AIPMTAIPMT 1990Atoms

Solution:

$R=(A)^{1 / 3}$ from $R=R_{0} A^{1 / 3}$
$\therefore R_{A I}=(27)^{1 / 3}$ and $R_{T e}=(125)^{1 / 5}$
$\therefore \frac{R_{A I}}{R_{T e}}=\frac{3}{5}=\frac{6}{10}$