The ratio of the maximum wavelength of the Lyman series in hydrogen spectrum to the maximum wavelength in the Paschen series is

Question

The ratio of the maximum wavelength of the Lyman series in hydrogen spectrum to the maximum wavelength in the Paschen series is (A) (3/105) (B) (6/15) (C) (52/7) (D) (7/108)

Tardigrade Admin · Accepted Answer

(λ1/λ2)=(((1/9)-(1/16))/((1)1-(1)4)=(7/108)

Q. The ratio of the maximum wavelength of the Lyman series in hydrogen spectrum to the maximum wavelength in the Paschen series is

$\frac{3}{105}$

$\frac{6}{15}$

$\frac{52}{7}$

$\frac{7}{108}$

$\frac{λ _{1}}{λ _{2}} = \frac{( \frac{1}{9} - \frac{1}{16} )}{( \frac{1}{1} - \frac{1}{4} )} = \frac{7}{108}$

Q. The ratio of the maximum wavelength of the Lyman series in hydrogen spectrum to the maximum wavelength in the Paschen series is

1053​

156​

752​

1087​

λ2​λ1​​=(11​−41​)(91​−161​)​=1087​

$\frac{3}{105}$

$\frac{6}{15}$

$\frac{52}{7}$

$\frac{7}{108}$

$\frac{λ _{1}}{λ _{2}} = \frac{( \frac{1}{9} - \frac{1}{16} )}{( \frac{1}{1} - \frac{1}{4} )} = \frac{7}{108}$