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  4. The ratio of the maximum wavelength of the Lyman series in hydrogen spectrum to the maximum wavelength in the Paschen series is

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Q. The ratio of the maximum wavelength of the Lyman series in hydrogen spectrum to the maximum wavelength in the Paschen series is

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Solution:

$\frac{\lambda_1}{\lambda_2}=\frac{\left(\frac{1}{9}-\frac{1}{16}\right)}{\left(\frac{1}{1}-\frac{1}{4}\right)}=\frac{7}{108}$