Question

The ratio of the density of oxygen nucleus $\left({}_8^{16}O\right)$ and helium nucleus $\left({}_2^{4}He\right)$ is

• A. $4:1$
• B. $1:1$
• C. $8:1$
• D. $2:1$

Answer 1

Answer: (B)

Nuclear density is independent of mass number As nuclear density $=\frac{Au}{\frac{4}{3}\pi R^3}$
Also, $R=R_0{A}^{\frac{1}{3}}$
And $R^3=R_0^{3}A$
$\Rightarrow$ Nuclear density $=\frac{Au}{\frac{4}{3}\pi R_0^{3}A}$
Nuclear density $=\frac{3u}{4\pi R_0^3}$
$\Rightarrow$ Nuclear density is independent of $A$