Question

The ratio of the density of oxygen nucleus $\left({ }_8^{16} O \right)$ and helium nucleus $\left({ }_2^4 He \right)$ is

• A. $4: 1$
• B. $1: 1$
• C. $8: 1$
• D. $2: 1$

Answer 1

Answer: (B)

Nuclear density is independent of mass number As nuclear density $=\frac{ Au }{\frac{4}{3} \pi R ^3}$
Also, $R = R _0 A ^{\frac{1}{3}}$
And $R ^3= R _0^3 A$
$\Rightarrow$ Nuclear density $=\frac{ Au }{\frac{4}{3} \pi R _0^3 A }$
Nuclear density $=\frac{3 u }{4 \pi R _0^3}$
$\Rightarrow$ Nuclear density is independent of $A$