Question

The ratio of magnitude of electric displacement and electric field $(E)$ is

• A. charge density
• B. permittivity
• C. electric susceptibility
• D. dielectric constant

Answer 1

Answer: (B)

The dimension of electric displacement
$D=$ [Dimension of ${\epsilon }_0$ ] [Dimension of $E$]
So $\frac{[D]}{[E]}=\frac{[{\epsilon }_0][E]}{[E]}=[{\epsilon }_0]$
So, $\frac{D}{E}=$ Permittivity