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  4. The ratio of magnitude of electric displacement and electric field (E) is

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Q. The ratio of magnitude of electric displacement and electric field $(E)$ is

J & K CETJ & K CET 2014

Solution:

The dimension of electric displacement
$D =$ [Dimension of $ \varepsilon_{0} $ ] [Dimension of $E$]
So $ \frac{[D]}{[E]}=\frac{[\varepsilon _{0}][E]}{[E]}=[\varepsilon _{0}] $
So, $ \frac{D}{E}= $ Permittivity