Question

The ratio of kinetic energy to total energy, for $n^{\text{th}}$ shell of an atom will be:

• A. 1
• B. -1
• C. ${}_{l}2$
• D. $\frac{1}{n^2}$

Answer 1

Answer: (B)

Kinetic energy $K=\frac{Z{e}^2}{8\pi {\epsilon }_{0}r}$
Total energy $U=\frac{-Z{e}^2}{8\pi {\epsilon }_{0}r}$
$K:U=1:-1=-1$