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Q. The ratio of kinetic energy to total energy, for $ n^{\text{th}} $ shell of an atom will be:

Rajasthan PMTRajasthan PMT 2002Atoms

Solution:

Kinetic energy $K=\frac{Z e^{2}}{8 \pi \varepsilon_{0} r}$
Total energy $U=\frac{-Z e^{2}}{8 \pi \varepsilon_{0} r}$
$K: U=1:-1=-1$