Question

The ratio of ionization energy of $H$ and $B{e}^{+3}$ is

• A. 1: 1
• B. 1: 3
• C. 1: 9
• D. 1: 16

Answer 1

Answer: (D)

Ionisation energy of $H$ atom $=13.6eV$

Here, $B{e}^{(3+)}$ is $H$ like atom.

$\therefore$ Ionisation energy of $B{e}^{3+}$ ion $=13.6\times Z^2$

$=16\times 13.6eV$