1. Tardigrade
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  3. Chemistry
  4. The ratio of ionization energy of H and Be +3 is

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Q. The ratio of ionization energy of $H$ and $Be ^{+3}$ is

Structure of Atom

Solution:

Ionisation energy of $H$ atom $=13.6 eV$

Here, $Be ^{(3+)}$ is $H$ like atom.

$\therefore $ Ionisation energy of $Be ^{3+}$ ion $=13.6 \times Z ^{2}$

$=16 \times 13.6 eV$