The rate of the reaction, 3A + 2B → Products is given by the rate expression: Rate = k[A][B]2 If A is taken in excess, the order of the reaction would be

Question

The rate of the reaction, 3A + 2B → Products is given by the rate expression: Rate = k[A][B]2 If A is taken in excess, the order of the reaction would be (A) 3 (B) 2 (C) 1 (D) 5

Tardigrade Admin · Accepted Answer

When A is taken in excess, its concentration will become constant; the rate law may, therefore, be given as Rate =k'[B]2 order = 2.

Q. The rate of the reaction,
$3 A + 2 B \to$ Products is given by the rate expression:
Rate $= k [A] [B]^{2}$
If $A$ is taken in excess, the order of the reaction would be

$3$

$2$

$1$

$5$

When $A$ is taken in excess, its concentration will become constant; the rate law may, therefore, be given as
$R a t e = k^{'} [B]^{2}$ order $= 2$ .

Q. The rate of the reaction, 3A+2B→ Products is given by the rate expression: Rate =k[A][B]2 If A is taken in excess, the order of the reaction would be

3

2

1

5

When A is taken in excess, its concentration will become constant; the rate law may, therefore, be given as Rate=k′[B]2 order =2.

Q. The rate of the reaction,
$3 A + 2 B \to$ Products is given by the rate expression:
Rate $= k [A] [B]^{2}$
If $A$ is taken in excess, the order of the reaction would be

$3$

$2$

$1$

$5$

When $A$ is taken in excess, its concentration will become constant; the rate law may, therefore, be given as
$R a t e = k^{'} [B]^{2}$ order $= 2$ .