1. Tardigrade
  2. Question
  3. Chemistry
  4. The rate of the reaction, 3A + 2B → Products is given by the rate expression: Rate = k[A][B]2 If A is taken in excess, the order of the reaction would be

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Q. The rate of the reaction,
$3A + 2B \to$ Products is given by the rate expression:
Rate $= k\left[A\right]\left[B\right]^{2}$
If $A$ is taken in excess, the order of the reaction would be

Chemical Kinetics

Solution:

When $A$ is taken in excess, its concentration will become constant; the rate law may, therefore, be given as
$Rate =k'\left[B\right]^{2}$ order $ = 2$.