The rate of reaction, A+B → Products; is given by the equation r=k[A][B]. If B is taken in large excess, the order of the reaction would be

Question

The rate of reaction, A+B → Products; is given by the equation r=k[A][B]. If B is taken in large excess, the order of the reaction would be (A) 2 (B) 1 (C) 0 (D) unpredictable

Tardigrade Admin · Accepted Answer

r=k[A][B] If B is in large excess then rate becomes independent of [B] and will depend only on [A] . Therefore, the order of reaction with respect to [A] is one.

Q. The rate of reaction, $A + B \to$ Products; is given by the equation $r = k [A] [B]$ . If $B$ is taken in large excess, the order of the reaction would be

2

1

0

unpredictable

$r = k [A] [B]$

If $B$ is in large excess then rate becomes independent of $[B]$ and will depend only on $[A] .$ Therefore, the order of reaction with respect to $[A]$ is one.

Q. The rate of reaction, A+B→ Products; is given by the equation r=k[A][B]. If B is taken in large excess, the order of the reaction would be

2

1

0

unpredictable

r=k[A][B] If B is in large excess then rate becomes independent of [B] and will depend only on [A]. Therefore, the order of reaction with respect to [A] is one.

Q. The rate of reaction, $A + B \to$ Products; is given by the equation $r = k [A] [B]$ . If $B$ is taken in large excess, the order of the reaction would be

$r = k [A] [B]$

If $B$ is in large excess then rate becomes independent of $[B]$ and will depend only on $[A] .$ Therefore, the order of reaction with respect to $[A]$ is one.