Tardigrade
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Tardigrade
Question
Chemistry
The rate of free radical chlorination of CH4 is
Q. The rate of free radical chlorination of
C
H
4
is
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A
equal to
C
D
4
B
double the rate of
C
D
4
C
12 times the rate of
C
D
4
D
less than the rate of
C
D
4
Solution:
The rate of reaction of
C
H
4
is greater than
C
D
4
because the activation energy of
C
H
4
is less than the
C
D
4
.
Hence, the rate of free radical chlorination of
C
H
4
is greater than
C
D
4
.