Question

The rate of free radical chlorination of $ C{{H}_{4}} $ is

• A. equal to $ C{{D}_{4}} $
• B. double the rate of $ C{{D}_{4}} $
• C. 12 times the rate of $ C{{D}_{4}} $
• D. less than the rate of $ C{{D}_{4}} $

Answer 1

Answer: (C)

The rate of reaction of $ C{{H}_{4}} $ is greater than $ C{{D}_{4}} $ because the activation energy of $ C{{H}_{4}} $ is less than the $ C{{D}_{4}}. $ Hence, the rate of free radical chlorination of $ C{{H}_{4}} $ is greater than $ C{{D}_{4}}. $