The rate of formation of S03 in the reaction 2SO2 + O2 → 2SO3 is 100 g min-1. Hence, rate of disappearance of

Question

The rate of formation of S03 in the reaction 2SO2 + O2 → 2SO3 is 100 g min-1. Hence, rate of disappearance of (A) 50 g min-1 (B) 100 g min-1 (C) 20 g min-1 (D) 40 g min-1

Tardigrade Admin · Accepted Answer

Molar mass of SO3 = (32 + 16 × 3) g mol-1 =80 g mol-1 =. Rate of formation of SO3 = 100 g min-1 =(100/80)mol min-1 =(100/80)mol,min-1 . Rate of disappearance of O2 (1/2)× Rate of formation of SO3 =(100/80 × 2)mol min-1 Molar mass of O2 = 32 =(100/80 × 2)mol min-1=(100 × 32/809 × 2)g min-1 20 g min-1

Q. The rate of formation of $S 0_{3}$ in the reaction
$2 S O_{2} + O_{2} \to$ $2 S O_{3}$ is 100 g $mi n^{- 1}$ . Hence, rate of disappearance of

$50 g mi n^{- 1}$

$100 g mi n^{- 1}$

$20 g mi n^{- 1}$

$40 g mi n^{- 1}$

Q. The rate of formation of S03​ in the reaction 2SO2​+O2​→ 2SO3​ is 100 g min−1. Hence, rate of disappearance of

50gmin−1

100gmin−1

20gmin−1

40gmin−1

Q. The rate of formation of $S 0_{3}$ in the reaction
$2 S O_{2} + O_{2} \to$ $2 S O_{3}$ is 100 g $mi n^{- 1}$ . Hence, rate of disappearance of

$50 g mi n^{- 1}$

$100 g mi n^{- 1}$

$20 g mi n^{- 1}$

$40 g mi n^{- 1}$