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Q. The rate of formation of $S0_3$ in the reaction
$2SO_2 + O_2 \to$ $2SO_3$ is 100 g $min^{-1}$. Hence, rate of disappearance of

Chemical Kinetics

Solution:

Molar mass of $SO_3 = (32 + 16 \times 3) g mol^{-1}$
=80 g $mol^{-1}$
=. Rate of formation of $SO_3 = 100 g min^{-1}$
=$\frac{100}{80}mol\,min^{-1}$
=$\frac{100}{80}mol,min^{-1}$
. Rate of disappearance of $ O_2$
$\frac{1}{2}\times $ Rate of formation of $SO_3$
=$\frac{100}{80 \times 2}mol\,min^{-1}$
Molar mass of $O_2 = 32$
=$\frac{100}{80 \times 2}mol\,min^{-1}=\frac{100 \times 32}{809 \times 2}g \,min^{-1}$
$20 \,g\,min^{-1}$