The rate of flow of water in a capillary tube of length ℓ and radius r is V. The rate of flow in another capillary tube of length 4 ℓ and radius 2 r for same pressure difference would be

Question

The rate of flow of water in a capillary tube of length ℓ and radius r is V. The rate of flow in another capillary tube of length 4 ℓ and radius 2 r for same pressure difference would be (A) V (B) 4 V (C) 2 V (D) 8 V

Tardigrade Admin · Accepted Answer

V =( P π r 4/8 η l ) ; V 1=( P π(2 r )4/8 η(4 l ))=4 V

Q. The rate of flow of water in a capillary tube of length $ℓ$ and radius $r$ is $V$ . The rate of flow in another capillary tube of length $4 ℓ$ and radius $2 r$ for same pressure difference would be

$V$

$4 V$

$2 V$

$8 V$

$V = \frac{P π r ^{4}}{8 η l};$
$V^{1} = \frac{P π ( 2 r ) ^{4}}{8 η ( 4 l )} = 4 V$

Q. The rate of flow of water in a capillary tube of length ℓ and radius r is V. The rate of flow in another capillary tube of length 4ℓ and radius 2r for same pressure difference would be

V

4V

2V

8V

V=8ηlPπr4​; V1=8η(4l)Pπ(2r)4​=4V

Q. The rate of flow of water in a capillary tube of length $ℓ$ and radius $r$ is $V$ . The rate of flow in another capillary tube of length $4 ℓ$ and radius $2 r$ for same pressure difference would be

$V$

$4 V$

$2 V$

$8 V$

$V = \frac{P π r ^{4}}{8 η l};$
$V^{1} = \frac{P π ( 2 r ) ^{4}}{8 η ( 4 l )} = 4 V$