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Q. The rate of flow of water in a capillary tube of length $\ell$ and radius $r$ is $V$. The rate of flow in another capillary tube of length $4 \ell$ and radius $2 r$ for same pressure difference would be

Mechanical Properties of Fluids

Solution:

$V =\frac{ P \pi r ^{4}}{8 \eta l } ; $
$V ^{1}=\frac{ P \pi(2 r )^{4}}{8 \eta(4 l )}=4 V$