The rate of a gaseous reaction is given by the expression k[A][B]. If the volume of the reaction vessel is suddenly reduced to (1/4) th of the initial volume, the reaction rate relating to original rate will be

Question

The rate of a gaseous reaction is given by the expression k[A][B]. If the volume of the reaction vessel is suddenly reduced to (1/4) th of the initial volume, the reaction rate relating to original rate will be (A)  (1/10)  (B)  (1/8)  (C)  8  (D)  16

Tardigrade Admin · Accepted Answer

Rate = kab. When volume is reduced to 1/4th, concentrations will become 4 times. New rate =k(4a) (4b)=16 kab=16 times

Q. The rate of a gaseous reaction is given by the expression k[A][B]. If the volume of the reaction vessel is suddenly reduced to $\frac{1}{4}$ th of the initial volume, the reaction rate relating to original rate will be

$\frac{1}{10}$

$\frac{1}{8}$

$8$

$16$

Rate = kab. When volume is reduced to 1/4th, concentrations will become 4 times. New rate $= k (4 a) (4 b) = 16 kab = 16$ times

Q. The rate of a gaseous reaction is given by the expression k[A][B]. If the volume of the reaction vessel is suddenly reduced to 41​ th of the initial volume, the reaction rate relating to original rate will be

101​

81​

8

16

Rate = kab. When volume is reduced to 1/4th, concentrations will become 4 times. New rate =k(4a)(4b)=16kab=16 times

Q. The rate of a gaseous reaction is given by the expression k[A][B]. If the volume of the reaction vessel is suddenly reduced to $\frac{1}{4}$ th of the initial volume, the reaction rate relating to original rate will be

$\frac{1}{10}$

$\frac{1}{8}$

$8$

$16$

Rate = kab. When volume is reduced to 1/4th, concentrations will become 4 times. New rate $= k (4 a) (4 b) = 16 kab = 16$ times