1. Tardigrade
  2. Question
  3. Chemistry
  4. The rate of a gaseous reaction is given by the expression k[A][B]. If the volume of the reaction vessel is suddenly reduced to (1/4) th of the initial volume, the reaction rate relating to original rate will be

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Q. The rate of a gaseous reaction is given by the expression k[A][B]. If the volume of the reaction vessel is suddenly reduced to $ \frac{1}{4} $ th of the initial volume, the reaction rate relating to original rate will be

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Solution:

Rate = kab. When volume is reduced to 1/4th, concentrations will become 4 times. New rate $ =k(4a)\,(4b)=16\,kab=16 $ times