The rate of a first order reaction is 1.8 × 10-3 mol L -1 min -1 when the initial concentration is 0.3 mol L -1. The rate constant is

Question

The rate of a first order reaction is 1.8 × 10-3 mol L -1 min -1 when the initial concentration is 0.3 mol L -1. The rate constant is (A) 1 × 10-2 s -1 (B) 1 × 10-4 s -1 (C) 6 × 10-2 s -1 (D) 4 × 10-4 s -1

Tardigrade Admin · Accepted Answer

Rate = k [ A ] 1.8 × 10-3 mol L -1 min -1= k × 0.3 mol L -1 ∴ k =(1.8 × 10-3/0.3 × 60)=1 × 10-4 s -1

Q. The rate of a first order reaction is $1.8 \times 1 0^{- 3} m o l L^{- 1}$ $min^{- 1}$ when the initial concentration is $0.3 m o l L^{- 1}$ . The rate constant is

$1 \times 1 0^{- 2} s^{- 1}$

$1 \times 1 0^{- 4} s^{- 1}$

$6 \times 1 0^{- 2} s^{- 1}$

$4 \times 1 0^{- 4} s^{- 1}$

Rate $= k [A]$

$1.8 \times 1 0^{- 3} m o l L^{- 1} min - 1 = k \times 0.3 m o l L^{- 1}$

$∴ k = \frac{1.8 \times 1 0 ^{- 3}}{0.3 \times 60} = 1 \times 1 0^{- 4} s^{- 1}$

Q. The rate of a first order reaction is 1.8×10−3molL−1 min−1 when the initial concentration is 0.3molL−1. The rate constant is

1×10−2s−1

1×10−4s−1

6×10−2s−1

4×10−4s−1