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Q. The rate of a first order reaction is $1.8 \times 10^{-3}\, mol\, L ^{-1}$ $\min ^{-1}$ when the initial concentration is $0.3\, mol\, L ^{-1}$. The rate constant is

Chemical Kinetics

Solution:

Rate $= k [ A ]$

$1.8 \times 10^{-3}\, mol\, L ^{-1}\, \min -1= k \times 0.3\, mol\, L ^{-1}$

$\therefore k =\frac{1.8 \times 10^{-3}}{0.3 \times 60}=1 \times 10^{-4} s ^{-1}$