The rate constants of forward and backward reactions are 8.5 × 10-5 and 2.38 × 10-4 respectively. The equilibrium constant is

Question

The rate constants of forward and backward reactions are 8.5 × 10-5 and 2.38 × 10-4 respectively. The equilibrium constant is (A) 0.35 (B) 0.42 (C) 12.92 (D) 0.292

Tardigrade Admin · Accepted Answer

K = (kf/kb) = (8.5 × 10-5/2.38 × 10-4) = 0.35 .

Q. The rate constants of forward and backward reactions are $8.5 \times 1 0^{- 5}$ and $2.38 \times 1 0^{- 4}$ respectively. The equilibrium constant is

0.35

0.42

12.92

0.292

K = $\frac{k _{f}}{k _{b}} = \frac{8.5 \times 1 0 ^{- 5}}{2.38 \times 1 0 ^{- 4}}$ = 0.35 .

Q. The rate constants of forward and backward reactions are 8.5×10−5 and 2.38×10−4 respectively. The equilibrium constant is