1. Tardigrade
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  3. Chemistry
  4. The rate constants of forward and backward reactions are 8.5 × 10-5 and 2.38 × 10-4 respectively. The equilibrium constant is

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Q. The rate constants of forward and backward reactions are $8.5 \times 10^{-5}$ and $2.38 \times 10^{-4}$ respectively. The equilibrium constant is

Equilibrium

Solution:

K = $\frac{k_f}{k_b} = \frac{8.5 \times 10^{-5}}{2.38 \times 10^{-4}}$ = 0.35 .