The rate constant of a reaction with a virus is 3.3 × 10-4 s -1. Time required for the virus to become 75 % inactivated is

Question

The rate constant of a reaction with a virus is 3.3 × 10-4 s -1. Time required for the virus to become 75 % inactivated is (A) 35 min (B) 70 min (C) 105 min (D) 17.5 min

Tardigrade Admin · Accepted Answer

t1 / 2=(0.693/3.3 × 10-4)=2100 s =35 min t75 %=2 t1 / 2=2 × 35=70 min

Q. The rate constant of a reaction with a virus is $3.3 \times 1 0^{- 4}$ $s^{- 1}$ . Time required for the virus to become $75%$ inactivated is

$35 min$

$70 min$

$105 min$

$17.5 min$

$t_{1/2} = \frac{0.693}{3.3 \times 1 0 ^{- 4}} = 2100 s = 35 min$
$t_{75%} = 2 t_{1/2} = 2 \times 35 = 70 min$

Q. The rate constant of a reaction with a virus is 3.3×10−4 s−1. Time required for the virus to become 75% inactivated is

35min

70min

105min

17.5min