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  4. The rate constant of a reaction with a virus is 3.3 × 10-4 s -1. Time required for the virus to become 75 % inactivated is

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Q. The rate constant of a reaction with a virus is $3.3 \times 10^{-4}$ $s ^{-1}$. Time required for the virus to become $75 \%$ inactivated is

NEETNEET 2022Chemical Kinetics

Solution:

$t_{1 / 2}=\frac{0.693}{3.3 \times 10^{-4}}=2100\,s =35 \min$
$t_{75 \%}=2 t_{1 / 2}=2 \times 35=70 \min$