The rate constant for forward and backward reaction of hydrolysis of ester are 1.1 × 10-2 and 1.5 × 10-3 per minute respectively. Equilibrium constant for the reaction CH 3 COOC 2 H 5+ H + leftharpoons CH 3 COOH + C 2 H 5 OH is

Question

The rate constant for forward and backward reaction of hydrolysis of ester are 1.1 × 10-2 and 1.5 × 10-3 per minute respectively. Equilibrium constant for the reaction CH 3 COOC 2 H 5+ H + leftharpoons CH 3 COOH + C 2 H 5 OH is (A) 4.33 (B) 5.33 (C) 6.33 (D) 7.33

Tardigrade Admin · Accepted Answer

Rate constant of forward reaction (K)=1.1 × 10-2 and rate constant of backward reaction (Kb)=1.5 × 10-3 per minute. Equilibrium constant (Kc)=(Kf/Kb)=(1.1 × 10-2/1.5 × 10-3)=7.33

Q. The rate constant for forward and backward reaction of hydrolysis of ester are $1.1 \times 1 0^{- 2}$ and $1.5 \times 1 0^{- 3}$ per minute respectively. Equilibrium constant for the reaction $C H_{3} COO C_{2} H_{5} + H^{+} ⇌ C H_{3} COO H + C_{2} H_{5} O H$ is

4.33

5.33

6.33

7.33

Rate constant of forward reaction $(K) = 1.1 \times 1 0^{- 2}$ and rate constant of backward reaction $(K_{b}) = 1.5 \times 1 0^{- 3}$ per minute.
Equilibrium constant $(K_{c}) = \frac{K _{f}}{K _{b}} = \frac{1.1 \times 1 0 ^{- 2}}{1.5 \times 1 0 ^{- 3}} = 7.33$

Q. The rate constant for forward and backward reaction of hydrolysis of ester are 1.1×10−2 and 1.5×10−3 per minute respectively. Equilibrium constant for the reaction CH3​COOC2​H5​+H+⇌CH3​COOH+C2​H5​OH is