The radius of second Bohr's orbit of hydrogen atom is

Question

The radius of second Bohr's orbit of hydrogen atom is (A) 0.053 nm (B) 0.106 nm (C) 0.2116 nm (D) 0.4256 nm

Tardigrade Admin · Accepted Answer

Key Idea Bohr's radius is given by rn=(0.529 n2/Z) mathringA Bohr's orbit of hydrogen atom (n)=2 Atomic number of hydrogen (Z)=1 Therefore, rn=(0.529 ×(2)2/1) =0.529 × 4 rn =2.116 mathringA =0.2116 nm

Q. The radius of second Bohr's orbit of hydrogen atom is

0.053 nm

0.106 nm

0.2116 nm

0.4256 nm

Key Idea Bohr's radius is given by
$r_{n} = \frac{0.529 n ^{2}}{Z} \overset{˚}{A}$
Bohr's orbit of hydrogen atom $(n) = 2$
Atomic number of hydrogen $(Z) = 1$
Therefore, $r_{n} = \frac{0.529 \times ( 2 ) ^{2}}{1}$
$= 0.529 \times 4$
$r_{n} = 2.116 \overset{˚}{A}$
$= 0.2116 nm$

Q. The radius of second Bohr's orbit of hydrogen atom is

0.053 nm

0.106 nm

0.2116 nm

0.4256 nm

Key Idea Bohr's radius is given by rn​=Z0.529n2​A˚ Bohr's orbit of hydrogen atom (n)=2 Atomic number of hydrogen (Z)=1 Therefore, rn​=10.529×(2)2​ =0.529×4 rn​=2.116A˚ =0.2116nm

Key Idea Bohr's radius is given by
$r_{n} = \frac{0.529 n ^{2}}{Z} \overset{˚}{A}$
Bohr's orbit of hydrogen atom $(n) = 2$
Atomic number of hydrogen $(Z) = 1$
Therefore, $r_{n} = \frac{0.529 \times ( 2 ) ^{2}}{1}$
$= 0.529 \times 4$
$r_{n} = 2.116 \overset{˚}{A}$
$= 0.2116 nm$