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Q.
The radius of second Bohr's orbit of hydrogen atom is
AMUAMU 2005
Solution:
Key Idea Bohr's radius is given by
$r_{n}=\frac{0.529 n^{2}}{Z} \,\mathring{A}$
Bohr's orbit of hydrogen atom $(n)=2$
Atomic number of hydrogen $(Z)=1$
Therefore, $r_{n}=\frac{0.529 \times(2)^{2}}{1}$
$=0.529 \times 4 $
$r_{n} =2.116 \,\mathring{A}$
$=0.2116 \,nm$