The radius of second Bohrs orbit of hydrogen atom is:

Question

The radius of second Bohrs orbit of hydrogen atom is: (A) 0.053 nm (B) 0.106 nm (C) 0.2116 nm (D) 0.4256 nm

Tardigrade Admin · Accepted Answer

Given that: Bohr's orbit of hydrogen atom (n)=2 Atomic number of hydrogen (z)=1 By using: r =(0.529 n2/z) =(0.529 ×(2)2/1) =(0.529 × 4/1) =2.116 mathringA =0.2116 nm

Q. The radius of second Bohrs orbit of hydrogen atom is:

0.053 nm

0.106 nm

0.2116 nm

0.4256 nm

Given that :
Bohr's orbit of hydrogen atom $(n) = 2$
Atomic number of hydrogen $(z) = 1$
By using :
$r = \frac{0.529 n ^{2}}{z}$
$= \frac{0.529 \times ( 2 ) ^{2}}{1}$
$= \frac{0.529 \times 4}{1}$
$= 2.116 \overset{˚}{A}$
$= 0.2116 nm$

Q. The radius of second Bohrs orbit of hydrogen atom is:

0.053 nm

0.106 nm

0.2116 nm

0.4256 nm

Given that : Bohr's orbit of hydrogen atom (n)=2 Atomic number of hydrogen (z)=1 By using : r=z0.529n2​ =10.529×(2)2​ =10.529×4​ =2.116A˚ =0.2116nm

Given that :
Bohr's orbit of hydrogen atom $(n) = 2$
Atomic number of hydrogen $(z) = 1$
By using :
$r = \frac{0.529 n ^{2}}{z}$
$= \frac{0.529 \times ( 2 ) ^{2}}{1}$
$= \frac{0.529 \times 4}{1}$
$= 2.116 \overset{˚}{A}$
$= 0.2116 nm$