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Q. The radius of second Bohrs orbit of hydrogen atom is:

ManipalManipal 2004Structure of Atom

Solution:

Given that :
Bohr's orbit of hydrogen atom $(n)=2$
Atomic number of hydrogen $(z)=1$
By using :
$r =\frac{0.529 n^{2}}{z} $
$=\frac{0.529 \times(2)^{2}}{1} $
$=\frac{0.529 \times 4}{1} $
$=2.116 \,\mathring{A}$
$=0.2116 \,nm$