The radius of gyration of a uniform rod of length L about an axis passing through its centre of mass and perpendicular to its length is

Question

The radius of gyration of a uniform rod of length L about an axis passing through its centre of mass and perpendicular to its length is (A) (L/√12) (B) (L2/√12) (C) (L/√3) (D) (L/√2)

Tardigrade Admin · Accepted Answer

K=√(I/M)=√(M L2 / 12/M)=(L/√12)

Q. The radius of gyration of a uniform rod of length $L$ about an axis passing through its centre of mass and perpendicular to its length is

$\frac{L}{12}$

$\frac{L ^{2}}{12}$

$\frac{L}{3}$

$\frac{L}{2}$

$K = \frac{I}{M} = \frac{M L ^{2} /12}{M} = \frac{L}{12}$

Q. The radius of gyration of a uniform rod of length L about an axis passing through its centre of mass and perpendicular to its length is

12​L​

12​L2​

3​L​

2​L​