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  4. The radius of gyration of a uniform rod of length L about an axis passing through its centre of mass and perpendicular to its length is

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Q. The radius of gyration of a uniform rod of length $L$ about an axis passing through its centre of mass and perpendicular to its length is

System of Particles and Rotational Motion

Solution:

$K=\sqrt{\frac{I}{M}}=\sqrt{\frac{M L^{2} / 12}{M}}=\frac{L}{\sqrt{12}}$