The radius of earth is 6400 km and g=10 m / s 2 . In order that a body of 5 kg weight is zero at the equator, the angular speed is

Question

The radius of earth is 6400 km and g=10 m / s 2 . In order that a body of 5 kg weight is zero at the equator, the angular speed is (A) (1/800) rad / sec (B) (1/1600) rad / sec (C) (1/400) rad / sec (D) (1/80) rad / sec

Tardigrade Admin · Accepted Answer

g'=0 and g=R ω2 ω =√(g/R)=√(10/6400 × 103) =(1/800) rad / sec

Q. The radius of earth is $6400 km$ and $g = 10 m / s^{2} .$ In order that a body of $5 k g$ weight is zero at the equator, the angular speed is

$\frac{1}{800}$ rad / \sec

$\frac{1}{1600}$ rad / sec

$\frac{1}{400}$ rad / sec

$\frac{1}{80}$ rad / sec

$g^{'} = 0$ and $g = R ω^{2}$
$ω = \frac{g}{R} = \frac{10}{6400 \times 1 0 ^{3}}$
$= \frac{1}{800}$ rad / sec

Q. The radius of earth is 6400km and g=10m/s2. In order that a body of 5kg weight is zero at the equator, the angular speed is

8001​ rad / \sec

16001​ rad / sec

4001​ rad / sec

801​ rad / sec