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  4. The radius of earth is 6400 km and g=10 m / s 2 . In order that a body of 5 kg weight is zero at the equator, the angular speed is

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Q. The radius of earth is $6400\, km$ and $g=10 \,m / s ^{2} .$ In order that a body of $5 \,kg$ weight is zero at the equator, the angular speed is

JIPMERJIPMER 2003Gravitation

Solution:

$g'=0$ and $g=R \omega^{2}$
$\omega =\sqrt{\frac{g}{R}}=\sqrt{\frac{10}{6400 \times 10^{3}}} $
$=\frac{1}{800}$ rad / sec